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The charges per hour of internet surfing...

The charges per hour of internet surfing is increased by 25% then find the percentage decrease in the time period of surfing of a user (a net savy) who can afford only a 10% increase in expenditure :

A

22%

B

12%

C

15%

D

9.09%

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AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow these calculations: ### Step 1: Define the original expenditure Let the original charges per hour be \( C \) and the original time period of surfing be \( T \). Therefore, the original expenditure \( E \) can be expressed as: \[ E = C \times T \] **Hint:** The expenditure is calculated by multiplying the charge per hour by the time spent. ### Step 2: Calculate the new expenditure after a 10% increase Given that the user can afford only a 10% increase in expenditure, the new expenditure \( E' \) is: \[ E' = E + 0.1E = 1.1E \] **Hint:** To find the new expenditure after a percentage increase, multiply the original expenditure by \( (1 + \text{percentage increase}) \). ### Step 3: Calculate the new charges after a 25% increase The charges per hour increase by 25%. Therefore, the new charges per hour \( C' \) can be calculated as: \[ C' = C + 0.25C = 1.25C \] **Hint:** A percentage increase can be calculated by multiplying the original amount by \( (1 + \text{percentage increase}) \). ### Step 4: Set up the equation for the new time period Since the new expenditure must equal the new charges multiplied by the new time period \( T' \), we have: \[ E' = C' \times T' \] Substituting the values of \( E' \) and \( C' \): \[ 1.1E = 1.25C \times T' \] ### Step 5: Substitute the original expenditure into the equation We know that \( E = C \times T \), so we can substitute \( E \) into the equation: \[ 1.1(C \times T) = 1.25C \times T' \] ### Step 6: Simplify the equation Dividing both sides by \( C \) (assuming \( C \neq 0 \)): \[ 1.1T = 1.25T' \] ### Step 7: Solve for the new time period \( T' \) Rearranging gives: \[ T' = \frac{1.1T}{1.25} \] To simplify: \[ T' = \frac{1.1}{1.25}T = \frac{11}{12.5}T = \frac{11 \times 8}{100}T = \frac{88}{100}T = 0.88T \] ### Step 8: Calculate the decrease in time period The decrease in time period is: \[ \text{Decrease} = T - T' = T - 0.88T = 0.12T \] ### Step 9: Calculate the percentage decrease The percentage decrease can be calculated as: \[ \text{Percentage Decrease} = \left( \frac{\text{Decrease}}{T} \right) \times 100 = \left( \frac{0.12T}{T} \right) \times 100 = 12\% \] ### Final Answer The percentage decrease in the time period of surfing is **12%**. ---
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