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Find the altitude and base of an isoscel...

Find the altitude and base of an isosceles triangle whose vertical angle is `65^(@)` and whose equal sides are 415 cm :

A

350 cm, 646 cm

B

350 cm, 446 cm

C

630 cm, 445 cm

D

none of these

Text Solution

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The correct Answer is:
To solve the problem of finding the altitude and base of an isosceles triangle with a vertical angle of \(65^\circ\) and equal sides of \(415 \, \text{cm}\), we can follow these steps: ### Step 1: Determine the Angles of the Triangle Since the triangle is isosceles, the two base angles are equal. The sum of the angles in a triangle is \(180^\circ\). Therefore, we can find the base angles as follows: \[ \text{Base angles} = \frac{180^\circ - 65^\circ}{2} = \frac{115^\circ}{2} = 57.5^\circ \] ### Step 2: Set Up the Triangle Let’s denote the triangle as \(ABC\) where \(A\) is the vertex with the angle of \(65^\circ\), and \(B\) and \(C\) are the other two vertices. The equal sides \(AB\) and \(AC\) are both \(415 \, \text{cm}\). The altitude \(AD\) from vertex \(A\) to the base \(BC\) will bisect the base \(BC\) into two equal parts, each of length \(\frac{x}{2}\), where \(x\) is the length of the base \(BC\). ### Step 3: Use Trigonometric Ratios to Find the Altitude Using the sine function for angle \(57.5^\circ\): \[ \sin(57.5^\circ) = \frac{\text{Altitude (AD)}}{\text{Hypotenuse (AB)}} \] Substituting the known values: \[ \sin(57.5^\circ) = \frac{h}{415} \] Calculating \(\sin(57.5^\circ\): \[ \sin(57.5^\circ) \approx 0.8434 \] Setting up the equation: \[ 0.8434 = \frac{h}{415} \] Now, solve for \(h\): \[ h = 415 \times 0.8434 \approx 350 \, \text{cm} \] ### Step 4: Use the Cosine Function to Find the Base Now, we can use the cosine function for angle \(57.5^\circ\): \[ \cos(57.5^\circ) = \frac{\frac{x}{2}}{415} \] Calculating \(\cos(57.5^\circ\): \[ \cos(57.5^\circ) \approx 0.5373 \] Setting up the equation: \[ 0.5373 = \frac{\frac{x}{2}}{415} \] Now, solve for \(x\): \[ \frac{x}{2} = 415 \times 0.5373 \] Calculating the right side: \[ \frac{x}{2} \approx 445.7 \] Thus: \[ x \approx 2 \times 445.7 \approx 891.4 \, \text{cm} \] ### Final Results - **Altitude (h)**: \(350 \, \text{cm}\) - **Base (x)**: \(891.4 \, \text{cm}\)
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