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If from point 100 m above the ground the...

If from point 100 m above the ground the angles of depression of two objects due south on the ground are `60^(@) and 45^(@)`, then the distance between the objects is :

A

`(50(3-sqrt3))/(3)m`

B

`(50(3+sqrt3))/(3)m`

C

`(100(3+sqrt3))/(3)m`

D

`(100(3-sqrt3))/(3)m`

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The correct Answer is:
To solve the problem, we need to find the distance between two objects on the ground based on the angles of depression from a point 100 m above the ground. ### Step-by-Step Solution: 1. **Understanding the Scenario**: - We have a point (let's call it A) that is 100 m above the ground. - From point A, the angles of depression to two objects on the ground are 60° and 45°. 2. **Drawing the Diagram**: - Draw a vertical line representing the height of 100 m (point A). - Draw horizontal lines from point A to the two objects on the ground (let's call them O1 and O2). - The angle of depression to O1 is 60° and to O2 is 45°. 3. **Identifying the Triangles**: - From point A to O1, we can form a right triangle (A-O1) where: - The height (opposite side) = 100 m - The angle of depression = 60° - From point A to O2, we can form another right triangle (A-O2) where: - The height (opposite side) = 100 m - The angle of depression = 45° 4. **Calculating Distances**: - For triangle A-O1 (with angle 60°): - Using the tangent function: \[ \tan(60°) = \frac{\text{opposite}}{\text{adjacent}} = \frac{100}{x_2} \] - Rearranging gives: \[ x_2 = \frac{100}{\tan(60°)} = \frac{100}{\sqrt{3}} \approx 100 \cdot \frac{1}{\sqrt{3}} = 100\sqrt{3} \text{ m} \] - For triangle A-O2 (with angle 45°): - Using the tangent function: \[ \tan(45°) = \frac{\text{opposite}}{\text{adjacent}} = \frac{100}{x_1} \] - Rearranging gives: \[ x_1 = \frac{100}{\tan(45°)} = 100 \text{ m} \] 5. **Finding the Distance Between the Objects**: - The distance between the two objects O1 and O2 (let's call it d) is: \[ d = x_1 - x_2 = 100 - 100\sqrt{3} \] - Simplifying gives: \[ d = 100(1 - \sqrt{3}) \text{ m} \] 6. **Final Answer**: - The distance between the two objects is: \[ d = 100(1 - \sqrt{3}) \text{ m} \]
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ARIHANT SSC-TRIGONOMETRY-EXERCISE(LEVEL - 1)
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  8. If the arcs of the same length in two circles subtend angles of 60^(@)...

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  14. The value of sin105^(@) is :

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  15. If tan theta=t, then sin 2theta is equal to :

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  16. If tan theta=sqrt2, then the value of theta is :

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  17. If tan theta=2-sqrt3, then tan(90-theta) is equal to :

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  18. If from point 100 m above the ground the angles of depression of two o...

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