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A kite is flown with a thread of 250 m l...

A kite is flown with a thread of 250 m length. If the thread is assumed to be stretched and makes an angle of `60^(@)` with the horizontal, then the height of the kite above the ground is (approx.) :

A

216.25 m

B

215.25 m

C

212.25 m

D

210.25 m

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The correct Answer is:
To find the height of the kite above the ground, we can use basic trigonometry. Here's the step-by-step solution: ### Step 1: Understand the problem We have a kite being flown with a thread of length 250 meters, making an angle of 60 degrees with the horizontal. We need to find the vertical height of the kite above the ground. ### Step 2: Draw a diagram Visualize the situation: - Draw a horizontal line representing the ground. - Draw a vertical line representing the height of the kite. - Draw the kite and the thread making an angle of 60 degrees with the horizontal. ### Step 3: Identify the right triangle The thread forms a right triangle with: - The length of the thread as the hypotenuse (250 m). - The height of the kite as the opposite side to the angle (60 degrees). - The horizontal distance as the adjacent side. ### Step 4: Use the sine function In a right triangle, the sine of an angle is defined as the ratio of the length of the opposite side to the length of the hypotenuse. Therefore, we can write: \[ \sin(\theta) = \frac{\text{Opposite}}{\text{Hypotenuse}} \] For our case: \[ \sin(60^\circ) = \frac{\text{Height}}{250} \] ### Step 5: Substitute the values We know that: \[ \sin(60^\circ) = \frac{\sqrt{3}}{2} \] Now, substituting this into the equation: \[ \frac{\sqrt{3}}{2} = \frac{\text{Height}}{250} \] ### Step 6: Solve for the height To find the height, we can rearrange the equation: \[ \text{Height} = 250 \cdot \frac{\sqrt{3}}{2} \] Calculating this gives: \[ \text{Height} = 250 \cdot 0.866 \approx 216.5 \text{ meters} \] ### Step 7: Final calculation To be more precise, using the exact value of \(\sqrt{3} \approx 1.732\): \[ \text{Height} = 250 \cdot \frac{1.732}{2} = 250 \cdot 0.866 = 216.5 \text{ meters} \] ### Conclusion Thus, the height of the kite above the ground is approximately **216.5 meters**. ---
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ARIHANT SSC-TRIGONOMETRY-EXERCISE(LEVEL - 1)
  1. From the Masthead of a ship, the angle of Depression of boat is 60^@, ...

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  2. A portion of a 30 m long tree is broken by tornado and the top struck ...

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  3. Two posts are 25 m and 15 m high and the line joining their tips makes...

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  4. The angle of elevation of the top of a tower at a point G on the groun...

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  5. If x=sec theta+tan theta, y = sec theta-tan theta, then the relation b...

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  6. The value of theta for which sqrt3 cos theta-sin theta=1 is :

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  7. If tan theta =(4)/(3), then the value of sqrt((1+cos theta)/(1-cos the...

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  8. If the arcs of the same length in two circles subtend angles of 60^(@)...

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  9. In the third quadrant, the values of sin theta and cos theta are :

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  10. The value of (cot 40^(@))/(tan50^(@))-(1)/(2)(cos35^(@))/(sin55^(@)) i...

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  11. The value of theta(0le theta le pi//2) stisfying the equation sin^(2)t...

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  12. If cos theta=(4)/(5) and 0lt theta lt 90^(@), then the value of (3cos ...

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  13. Maximum value of (cos theta-sin theta) is :

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  14. The value of sin105^(@) is :

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  15. If tan theta=t, then sin 2theta is equal to :

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  16. If tan theta=sqrt2, then the value of theta is :

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  17. If tan theta=2-sqrt3, then tan(90-theta) is equal to :

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  18. If from point 100 m above the ground the angles of depression of two o...

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  19. If the length of shadow of a vertical pole on the horizontal ground is...

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  20. A kite is flown with a thread of 250 m length. If the thread is assume...

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