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In a DeltaABC, AB=AC and AD|BC, then:...

In a `DeltaABC, AB=AC and AD_|_BC`, then:

A

`AB lt AD`

B

`AB gt AD`

C

`AB=AD`

D

`ABleAD`

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The correct Answer is:
To solve the problem step by step, we will analyze the given information and derive the relationship between the segments in triangle ABC. ### Step-by-Step Solution: 1. **Identify the Triangle**: We have triangle ABC where AB = AC, indicating that it is an isosceles triangle. **Hint**: Recall that in an isosceles triangle, the two sides opposite the equal angles are equal. 2. **Draw the Perpendicular**: A perpendicular line AD is drawn from point A to line BC. This means that AD is the altitude of the triangle from vertex A to side BC. **Hint**: Remember that the altitude of a triangle is a line segment from a vertex perpendicular to the opposite side. 3. **Properties of Isosceles Triangle**: Since triangle ABC is isosceles (AB = AC), the altitude AD also acts as the median to side BC. This means that point D, where AD meets BC, divides BC into two equal segments, BD and DC. **Hint**: In an isosceles triangle, the altitude from the vertex to the base bisects the base. 4. **Analyze the Right Triangle**: In triangle ABD, we have a right triangle where AD is the altitude, AB is one of the equal sides, and BD is half of the base BC. **Hint**: Use the Pythagorean theorem to analyze the relationship between the sides of the right triangle. 5. **Apply the Pythagorean Theorem**: According to the Pythagorean theorem: \[ AB^2 = AD^2 + BD^2 \] Since BD is a positive length, it follows that: \[ AD^2 < AB^2 \] Taking the square root of both sides gives: \[ AD < AB \] **Hint**: The Pythagorean theorem states that in a right triangle, the square of the hypotenuse (AB) is equal to the sum of the squares of the other two sides (AD and BD). 6. **Conclusion**: Since we have established that AD < AB, we can conclude that AB is greater than AD. Therefore, the correct option is: - AB > AD **Hint**: Compare the lengths of the altitude and the sides of the triangle to determine their relationships. ### Final Answer: AB is greater than AD (Option 2).
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ARIHANT SSC-GEOMETRY-INTRODUCTORY EXERCISE - 12.2
  1. In DeltaABC, AB=5cm, AC=7cm. If AD is the angle bisector of angleA The...

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  2. In a DeltaABC, D is the mid - point of BC and E is mid - point of AD, ...

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  3. In a DeltaABC, AB=AC and AD|BC, then:

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  4. The difference between altitude and base of a right angled triangle is...

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  5. If AB, BC and AC be the three sides of a triangle ABC, then which one ...

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  6. In the triangle ABC, side BC is produced to D. angleACD=100^(@) if BC ...

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  7. In the adjoining figure D, E and F are the mid - points of the sides B...

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  8. In the adjoining figure angleBAC=60^(@) and BC = a, AC = b and AB = c,...

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  9. In the adjoining figure of DeltaABC, angleBCA=120^(@) and AB = c, BC =...

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  10. In a right angled DeltaABC, angleC=90^(@) and CD is the perpendicular ...

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  11. If the medians of a triangle are equal, then the triangle is

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  12. The incentre of a triangle is determined by the :

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  13. The circumcentre of a triangle is determined by the :

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  14. The point of intersection of the angle bisectors of a triangle is :

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  15. The diagonal of the square field measures 50m. The area of square fiel...

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  16. If in a DeltaABC,'S' is the circumcentre then :

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  17. If AD, BE, CF are the altitudes of DeltaABC whose orthocentre is H, th...

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  18. In a right angled DeltaABC, angleC=90^(@) and CD is the perpendicular ...

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  19. In an equilateral triangle ABC, if a, b and c denote the lengths of pe...

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  20. What is the ratio of side to the height of an equilateral triangle?

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