if the roots of the equation` (x-a)/(ax-1) = (x-b)/(bx+1)` are reciprocal to each other. then a. a=1 b. b=2 c. a=2b d. b=0

If the roots of the equation ax^2+bx+c=0 (a!=0) are reciprocal to each other then a) a=b b) a=c c) b=c d) b^2=4ac

The roots of the equation ax^(2)+bx+c=0 will be reciprocal of each other if

The roots of the equation ax^2+bx+c=0 will be reciprocal of each other if a)a=b b)c=a c)b=c d)None of these

If the roots of the equation (x^(2)-bx)/(ax-c)=(m-1)/(m+1) are equal to opposite sign,then the value of m will be (a-b)/(a+b) b.(b-a)/(a+b) c.(a+b)/(a-b) d.(b+a)/(b-a)

If a root of the equation ax^(2)+bx+c=0 be reciprocal of a root of the equation a'x^(2)+b'x+c'=0 then

If one of the roots of the equation ax^2 + bx + c = 0 be reciprocal of one of the a_1 x^2 + b_1 x + c_1 = 0 , then prove that (a a_1-c c_1)^2 =(bc_1-ab_1) (b_1c-a_1 b) .

If one of the roots of the equation a(b-c)x^(2)+b(c-a)x+c(a-b)=0 is 1, the other root is

If one root of the equation ax^(2) + bx + c =0 is reciprocal of the one root of the equation a_(1)x^(2) + b_(1) x + c_(1) = 0 , then :