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A trapezium PQRS inscribes a circle whic...

A trapezium PQRS inscribes a circle which touches the circle at M, A, N, B, Radius of circle is 10 cm. The length of each non-parallel side is 21 cm. What is the perimeter of trapezium?

A

A)82 cm

B

B)84 cm

C

C)85.5 cm

D

D)can't be determined

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The correct Answer is:
To find the perimeter of trapezium PQRS that inscribes a circle, we can follow these steps: ### Step 1: Understand the properties of the trapezium Since trapezium PQRS inscribes a circle, it means that the sum of the lengths of the opposite sides are equal. This can be expressed as: \[ PQ + SR = PS + QR \] ### Step 2: Assign known values From the problem, we know: - The radius of the circle (r) = 10 cm - The lengths of the non-parallel sides (PS and QR) = 21 cm each. ### Step 3: Calculate the sum of the lengths of the non-parallel sides Since both non-parallel sides are equal: \[ PS + QR = 21 + 21 = 42 \, \text{cm} \] ### Step 4: Use the property of the trapezium to find the lengths of the parallel sides Let \( PQ = x \) and \( SR = y \). According to the property of the trapezium: \[ x + y = 42 \] ### Step 5: Express the perimeter of the trapezium The perimeter (P) of trapezium PQRS is the sum of all its sides: \[ P = PQ + QR + RS + PS \] Substituting the known values: \[ P = x + 21 + y + 21 \] \[ P = x + y + 42 \] ### Step 6: Substitute the value of \( x + y \) From Step 4, we know that \( x + y = 42 \): \[ P = 42 + 42 \] \[ P = 84 \, \text{cm} \] ### Conclusion The perimeter of trapezium PQRS is **84 cm**. ---
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