दो समतलों `2x+3y+4z=4` और `4x+6y+8z=12` के बीच कि दुरी है:

Distance between the two planes: 2x + 3y + 4z = 4 and 4x + 6y + 8z = 12 is(A) 2 units (B) 4 units (C) 8 units (D) 2/(sqrt(29)) units

Distance between the planes 2x + 3y + 4z = 4 and 4x + 6y + 8z = 12 is :

Distance between two planes : 2x + 3y + 4z = 5 and 4x + 6y + 8z = 12 is :

Distance between two planes 2x + 3y + 4z = 4 and 4x + 6y + 8z = 16 is :

If x+y+z=19, x^2+y^2+z^2=133 and xz=y^2 , then the difference between z and x is : यदि x^2+y^2+z^2=133 तथा xz=y^2 है, तो z और x के बीच क्या अंतर है ?

Distance between the two planes : 2x + 3y + 4z = 4 and 4x + 6y + 8z = 12 is

Distance between the two planes: 2x + 3y + 4z = 4 and 4x + 6y + 8z = 12 is

Distance between the two planes 2x + 3y +4z -4=0 and 4x + 6 y + 8z = 12 is …….

Distance between the two planes: 2x+3y+4z=4 and 4x+6y+8z=12 is (A) 2units (B) 4units (C) 8units (D) units