" 1."int_(0)^(1)|cos x|dx=" wenem "

int_(0)^(1)cos^(-1)x dx=

int_(0)^(1)cos^(-1)x dx=

int_(0)^(1)cos^(-1)x dx

int_(0)^(pi/2)(1+cos x)dx

int_(0)^(1)y dx where x=cos2y

Evaluate: int_(0)^(1)|5x-3|dx( ii) int_(0)^( pi)|cos x|dx( iii) int_(-5)^(5)|x-2|dx( iv )int_(-1)^(1)e^(|x|)dx(v)int_(0)^(2)|x^(2)+2x-3|dx(v)int_(1)^(4)(|x-1|+|x-2|+|x-3|)dx( vi) int_(1)^(2)|x^(3)-x|dx

int_(0)^( pi)log(1+cos x)dx

int_(0)^(pi//2)(1)/(2+cos x)dx=

int_(0)^(pi/2)(1)/(6-cos x)dx