In a `DeltaABC`, cosecA(sinBcosC+cosBsinC)` is equal to

In DeltaABC,cosecA(sinBcosC+cosBsinC)=

In DeltaABC,cosecA(sinBcosC+cosBsinC)=

In DeltaABC,cosecA(sinBcosC+cosBsinC)=?

In a DeltaABC , cosecA (sinB cosC + cosB sinC) =

In a triangle ABC, cosecA (sinB cosC + cosB sinC) is :

In any DeltaABC,sum(cosA)/(bcosC+ccosB) is equal to

Select and write the correct answer from the given alternatives in each of the following:if ABC is a triangle,then cosecA(sinBcosC+cosBsinC) is =

In a /_\ABC , cosec A[sinB.cosC+cosB.sinC]= (A) c/a (B) a/c (C) 1 (D) none of these

In a /_\ABC , cosec A[sinB.cosC+cosB.sinC]= (A) c/a (B) a/c (C) 1 (D) none of these

In a DeltaABC sum((cotA+cotB)/(tanA+tanB)) is equal to