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cos(2pi/7)cos(4pi/7)*cos(6pi/7)...

`cos(2pi/7)cos(4pi/7)*cos(6pi/7)`

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Prove that cos((2pi)/7)cos((4pi)/7)cos((8pi)/7)=1/8

cos(pi/7)cos((2pi)/7)cos((4pi)/7)=

Prove that: cos(pi/7)cos((2pi)/7)cos((4pi)/7)=-1/8

Prove that: cos(pi/7)cos(2pi/7)cos(4pi/7)=-1/8,

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