निम्नलिखित को सिद्ध कीजिये- `(sinthetacos(90^(@)-theta)costheta)/(sec90^(@)-theta)+(costhetasin(90^(@)-theta)sintheta)/(cosec(90^(@)-theta))=sinthetacostheta`

sin theta cos(90^(@)-theta)+cos theta sin(90^(@)-theta)

Prove that : (sinthetacos(90^0-theta)costheta)/(sin(90^0-theta))+(costhetasin(90^0-theta)sintheta)/(cos(90^0-theta))=1

Prove that:a. costhetasin(90^@-theta)+sinthetacos(90^@-theta)=1

cos(90^@-theta)=sintheta .

sin(90^(@)-theta)costheta+cos(90^(@)-theta)sintheta= ………… .

Evaluate sinthetacos(90^(@)-theta)+costhetasin(90^(@)-theta) .

Evaluate sinthetacos(90^(@)-theta)+costhetasin(90^(@)-theta) .

Evaluate : sin theta cos theta - (sin theta cos (90^(@) - theta) cos theta)/( sec (90^(@) - theta)) - (cos theta sin (90^(@) - theta) sin theta)/( cosec (90^(@) - theta))

Prove that sinthetacos(90^(@)-theta)=sin^(2)theta

tan theta+tan(90^(@)-theta)=sec theta xx sec(90^(@)-theta)