If the circle x^(2)+y^(2)=4 bisects the ...

If the circle `x^(2)+y^(2)=4` bisects the circumference of the circle `x^(2)+y^(2)-2x+6y+a=0`, then 'a' equals

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Chord of first circle is diameter of second and the center of the chord is the center of the second circle.

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