The velocity-time relation of an object starting from rest is given by v=3t . When "v" is in "m/s" and "t" in seconds. The distance traversed in "3" seconds is:

the velcoity -time relation of an electron starting from rest is given by v=kt,where h=2 ms^(-2) .calculate the distance traversed in 3s.

The velocity-time relation of an electron starting from rest is given by u=id, where k=2m//s^(2) . The distance traversed in 3 sec is:-

The velocity of an object moving rectillinearly is given as a functiion of time by v=4t-3t^(2) where v is in m/s and t is in seconds. The average velociy if particle between t=0 to t=2 seconds is

If a man has a velocity varying with time given as v=3t^(2),v is in m//s and t in sec then : Find out his acceleration after 3 seconds :

The velocity v of a particle at any instant t moving in a straight line is given by v=s +1 where s meter is the distance travelled in t second what is the time taken by the particle to cover a distacne of 9m ?

Let the instantaneous velocity of a rocket, just after launching, be given by the expression v=2t+3t^2 (where v is in ms^-1 and t is in seconds). Find out the distance travelled by the rocket from t=2s to t=3s .

The velocity v of a body moving along a straight line varies with time t as v=2t^(2)e^(-t) , where v is in m/s and t is in second. The acceleration of body is zero at t =

The velocity ofacar travelling on a straight road is given by the equation v=6+8t-t^(2) where vis in meters per second and t in seconds. The instantaneous acceleration when t=4.5 s is :

If a man has a velocity varying with time given as v=3t^(2),v is in m//s and t in sec then : Find out his displacement after 2 seconds of his start :

A body of mass 5 kg at rest under the action of a force which gives its velocity given by v = 3 xx t m//s , here 't' is time in seconds. The work done by the force in two seconds will be