If resistors of resistance `R_(1)` and `R_(2)` are connected in parallel,then resultant resistance is "

When two resistors of resistances R_1 and R_2 are connected in parallel, the net resistance is 3 Omega . When connected in series, its value is 16 Omega . Calculate the values of R_1 and R_2 .

Two resistors of resistance R_1 and R_2 having R_1>R_2 are connected in parallel. For equivalent resistance R, the correct statement is

Two resistors of resistance R_(1) and R_(2) having R_(1) gt R_(2) are connected in parallel. For equivalent resistance R, the correct statement is

Resistance R,2R,4R,8R ...... oo are connected in parallel. What is their resutlant resistance will be

The resultant resistance value of n resistance each of r ohms and connected is series is X. When those n , resistance are connected in parallel , the resultant values is .

Two resistor of resistance R_(1)=(6+-0.09)Omega and R_(2)=(3+-0.09)Omega are connected in parallel the equivalent resistance R with error (in Omega)

When resistors 1 and 2 are connected in series, the equivalent resistance is 20.0 Omega. When they are connected in parallel, the equivalent resistance is 3.75 Omega. What are (a) the smaller resistance and (b) the larger resistance of these two resistors?

The resultant resistance of n wires each of resistance r ohms is R ,when they are connected in parallel.When these n resistances are connected in series,the resultant resistance will be

The resultant resistance of n wires each of resistance r ohms is R, when they are connected in parallel. When these n resistances are connected in series, the resultant resistance will be