The central fringe shifts to the position of fifth bright fringe, if a thin film of refractive index 1.5 is introduced in the path of light of wavelength `5000 Å`. The thickness of the glass plate is

A central fringe of the interference pattern produced by a light of wavelength 6000Å is shifted to the position of 5th bright firnge when a glass plate of refractive index 1.5 is introduced in the path of the ray. Calculate the thickness of the glass plate.

In YDSE, the central bright fringe produced by light of wavelength 5600 Å shifts to the position of 5th bright fringe when a thin transparent film of refractive index 1.28 is introduced in the path of light from one of the two slits. Find the thickness of the film.

In Young's double slit experiment ,the central bright fringe produced by ligth of wavelength 5,600 overset@A shifts to the position of 5th brigth fringe,when thin transparent film of refractive index 1.28 is introduced in the path of light from one of two slits.Find the thickness of te film.

In a arrangement of Young experiment the central fringe of interference pattern produced by light of wavelength 6000 Å so the central fringe is superposing to 4th order dark fringe, after a glass plate of refractive index 1.5 is introduced. The thickness of the glass plate would be ......

The central fringe of the interference pattern produced by the light of wavelength 6000 Å is found to shift to the position of 4th dark fringe after a glass sheet of refractive index 1.5 is introduced. The thickness of glass sheet would be

The central fringe of the interference pattern produced by the light of wavelength 6000 Å is found to shift to the position of 4th dark fringe after a glass sheet of refractive index 1.5 is introduced. The thickness of glass sheet would be

A thin mica sheet of thickness 2xx10^-6m and refractive index (mu=1.5) is introduced in the path of the first wave. The wavelength of the wave used is 5000Å . The central bright maximum will shift