An area of cross-section of rubber string is `2 cm^(2)`. It length is doubled when stretched with a linear force of `2 xx 10^(5)` dynes. The Young's modulus of the rubber in `"dyne/cm"^(2)` will be

A string of cross section 2cm^2 is doubled in length by the application of a longitudinal force 2 xx 10^5 dynes. The youngs modulus is

A copper wire of length 4.0 mm and area of cross-section 1.2 cm^(2) is stretched with a force of 4.8 xx 10^(3) N. If Young's modulus for copper is 1.2xx10^(11) N//m^(2) , the increases in the length of the wire will be

A rubber cord of cross-sectional area 2 cm^(2) has a length of 1 m. When a tensile force of 10 N is applied, the length of the cord increases by 1 cm. What is the Young's modulus of rubber ?

A uniform wire of length 6m and a cross-sectional area 1.2 cm^(2) is stretched by a force of 600N . If the Young's modulus of the material of the wire 20xx 10^(10) Nm^(-2) , calculate (i) stress (ii) strain and (iii) increase in length of the wire.

The area of cross-section of steel wire is 0.1 cm^(2) and Young's modulus of steel is 2 times 10^(11)N" "m^(-1) . The force required to stretched by 0.1% of its length is

The area of a cross-section of steel wire is 0.1 cm^(-2) and Young's modulus of steel is 2 x 10^(11) N m^(-2) . The force required to stretch by 0.1% of its length is

The area of a cross-section of steel wire is 0.1 cm^(-2) and Young's modulus of steel is 2 x 10^(11) N m^(-2) . The force required to stretch by 0.1% of its length is