The wave function of `3s` electron is given by
`Psi_(3s)=1/(81sqrt(3)prod)(1/a_(0))^(3//2)[27-18(r/a_(0))+2(r/a_(0))^(2)]e^(-r//3a_(0))`
It has a node at `r=r_(0)`, Find out the relation between `r_(0)` and `a_(0)`

The wave inction of 3s electron is given by Psi =(1)/(81 sqrt(3)pi) ((1)/(a_(0)))^(3//2)[ 27-18 ((r )/(a_(0)))+2((r )/(a_(0)))^(3)] e^(r//3a_(0)) It has a node at r=r_(0) . Find the relation between r_(0) and a_(0) .

The wave function of 2s electron is given by W_(2s) = (1)/(4sqrt(2pi))((1)/(a_(0)))^(3//2)(2 - (r )/(a_(0)))e^(-1 a0) It has a node at r = r_(p) .Find the radiation between r_(p) and a

The Schrodinger wave equation for the 2s electron of a hydrogen atom is, psi_(2s)=(1)/(4sqrt(2pi))[(1)/(a_(0))]^(3//2)xx[2-(r)/(a_(0))]xxe^(-r//2a_(0)) There is a radial node at the point, where r=r_(0) find the relation between r_(0) and a_(0) .

The Wave function (Psi) of 2s is given by: Psi_(2s)=(1)/(2sqrt2pi)(1/a_(0))^(1//2){2-(r)/a^(0)}e^(-r//2a_(0)) At r =r_(0) , radial node is formed . Thus for 2s ,r_(0), in terms of a_(0) is-

The Schrodinger wave equation for hydrogen atom is Psi_(2s) = (1)/(4sqrt(2pi)) ((1)/(a_(0)))^(3//2) (2 - (r)/(a_(0))) e^(-r//a_(0)) , where a_(0) is Bohr's radius . If the radial node in 2s be at r_(0) , then r_(0) would be equal to :

The Schrodinger wave equation for hydrogen atom is Psi_(2s) = (1)/(4sqrt(2pi)) ((1)/(a_(0)))^(3//2) (2 - (r)/(a_(0))) e^(-r//a_(0)) , where a_(0) is Bohr's radius . If the radial node in 2s be at r_(0) , then r_(0) would be equal to :

The Schrodinger wave equation for hydrogen atom is Psi_(2s) = (1)/(4sqrt(2pi)) ((1)/(a_(0)))^(3//2) (2 - (r)/(a_(0))) e^(-r//a_(0)) , where a_(0) is Bohr's radius . If the radial node in 2s be at r_(0) , then r_(0) would be equal to :