A block of mass is kept on an inclined plane of a lift moving down with acceleration of `2 ms^(-2)` What should be the minimum coefficient of friction to let the block move down with constant velocity?

A block of mass m is kept on an inclined plane of a lift moving down with acceleration of 2 m//s^(-2). What should be the coefficient of friction to let the block move down with constant velocity relative to lift :

A block of mass m is kept on an inclined plane of a lift moving down with acceleration of 2m//s^(2) . What should be the coefficient of friction for the block to move down with constant velocity relative relative to lift?

Friction coefficient between block and inclined plane is [mu=1/sqrt(3)] if lift is moving vertically down with constant acceleration a then the value of acceleration a so that block moves down with constant velocity is

A block of mass 1kg is kept on the tilted floor of a lift moving down with acceleration 3ms^(-2) . If the block is released from rest as shown, what will be the time taken by block to reach the bottom? What is the normal reaction on the block during the motion?

A block of mass m is placed on a rough inclined plane of inclination theta kept on the floor of the lift. The coefficient of friction between the block and the inclined plane is mu . With what acceleration will the block slide down the inclined plane when the lift falls freely ?

A block of mass of 2 kg slides on an inclined plane that makes an angle of 30^(@) with the horizontal . The coefficient of friction between the block and the surface is sqrt(3)//2 . What force should be applied to the block so that it moves down without any acceleration ?

A block of mass m slides down an inclined plane of inclination theta with uniform speed The coefficient of friction between the block and the plane is mu . The contact force between the block and the plane is .