The values of x and y which make the following solutions true are: `cos x^0=sin 40^0 and cos y^0=sin (y^0+10)`

Solve the following determinant : det[[1,x,y0,cos x,sin y0,sin x,cos y]]

Solve the following determinant : det[[1,x,y0,cos x,sin y0,sin x,cos x]]

Solve the following differential equation (6)cos x cos y dy-sin x sin y dx=0

The value of alpha for which the system of linear equations: x+(sin alpha)y+(cos alpha)z=0,x+(cos alpha)y+(sin alpha)z=0,-x+(sin alpha)y+(-cos alpha)z=0 has a non - trivial solution could be

The solution the differential equation "cos x sin y dx" + "sin x cos y dy" =0 is

The solution the differential equation "cos x sin y dx" + "sin x cos y dy" =0 is

Let lambda and alpha be real.Find the set of all values of lambda for which the system of linear equations lambda x+(sin alpha)y+(cos alpha)z=0,x+(cos alpha)y+(sin alpha)z=0,quad -x+(sin alpha)y-(cos alpha)z=0

The normal form of the eqatuion of the line x+sqrt(3y) = 4 is (A) x cos 60^0 + y sin 60^0 = 2 (B) x cos 24^0 - y sin 24^0 - 2 (C) x cos 240^0 + y sin 240^0 - 2 (D) none of these

sin x cos y+(dy)/(dx)cos x sin y=0