The `K_(sp)` of CuS, `Ag_(2)S` and `HgS` are `10^(-31), 10^(-44)` and `10^(-54)` respectively. The solubility of these sulphides are in the order.

The K_(sp) of CuS, Ag_(2)S and HgS are 10^(-31), 10^(-44) and 10^(-54) respectively. The solubility of these hydrides are in the order :

The solubility product of CuS, Ag_2S and HgS are 10^(-31),10^(-44),10^(-54) respectively. The solubilities of these sulphides are in the order

The solubility product of CuS, Ag2S and HgS are 10^(-31),10^(-44),10^(-54) respectively. The solubility of these sulphides are in the order (a) Ag2S gt HgS gt CuS (b) HgS gt CdS gt CuS (c) Ag2S gt CuS gt HgS (d) CuS gt CdS gt HgS

The solubility product of CuS, CdS and HgS are 10^(-31),10^(-44),10^(-54) respectively. The solubility of these sulphides are in the order

The solubility products of CuS,Ag_2S and HgS are 10^(-31) , 4*10^(-44) and 10^(-54) respectively. If Na_2s is added in a solution containing 0.1 M Cu^2+ , Ag^2+ and Hg^2+ each then the

The solubility products of CuS,Ag_2S and HgS are 10^(-31) , 4*10^(-44) and 10^(-54) respectively. If Na_2s is added in a solution containing 0.1 M Cu^2+ , Ag^2+ and Hg^2+ each then the

A solution which is 10^(-3) M each in Mn^(2+), Fe^(2+), Zn^(3+) and Hg^(3) is is treated with 10^(-6) M sulphide ion. If K_(sp) of MnS , ZnS and HgS are 10^(-15) , 10^(-23), 10^(-20) and 10^(-54) respectively. Which of the following will be precipitated first?