The area of a parallelogram is equal to the product of a side of the parallelogram and the distance between any two sides.

Prove that twice the area of a parallelogram is equal in the area of another parallelogram formed by taking as its adjacent sides of the diagonals of the former parallelogram.

Show that the opposite sides of a parallelogram are equal.

ABCD is a parallelogram whose adjacent sides AB = 48 cm and BC = 14 cm . One of its diagonds AC = 50 cm . Find : (i) the area of the parallelogram ABCD. (ii) the distance between the longer sides. (iii) the distance between the shorter sides.

(ABCD is a quadrilateral with )/(AB)= .If the area of parallelogram ABCD is p xx the area of parallelogram ABCD is p xx the area of the parallelogram with AB,AD as adjacent sides,then p is equal to

ABCD is a parallelogram having adjacent sides AB = 35 cm and BC = 28 cm . If the distance between its longer sides is 8 cm , find : (i) the area of the parallelogram (ii) the distance between its shorts sides

Two adjacent sides of a parallelogram are 28 cm and 26 cm. If one diagonal of it is 30 cm long, Find the area of the parallelogram. Also, find the distance between shorter sides.

Two adjacent sides of a parallelogram are in the ratio of 5:3 and the perimeter of the parallelogram is 48cm. Then Find the length of each of its sides.

Let ABCD be a parallelogram with sides as given in the figure. Find the distance between the sides AB and DC.