Solubility of salt `A_(2)B_(3)` is `1 xx 10^(-4)`, its solubility product is

the solubility of A_(2)B_(3) is y mol dm^(-3) . Its solubility product is

The solubility of A_(2)B_(3) is S mol L^(-1) . Its solubility product is 108 s^(n) . The value of 'n' will be...........

The solubility of CaF_(2) is 2xx10^(-4)mol L^(-1) . Its solubility product is :

If the solubility of alum KAl(SO_4 )_2 is 2 xx 10^(-3) M, what its solubility product ?

The solubility of Ag_(2)CrO_(4) is 2 xx 10^(-2) "mol"//"lit" its solubility product is

The solubility of CaF_(2) is 2 xx 10^(-4) "mole"//"litre" . Its solubility product is

The solubility of CaF_(2) is 2 xx 10^(-4) "mole"//"litre" . Its solubility product is