The dimensions of permittivity `epsilon_(0)` are

The dimensional formula of permittivity (epsilon_0) of free space is :

The velocity of electromagnetic radiatior in a medium of permittivity epsilon_(0) and permeability mu_(0) is given by

The velocity of electromagnetic radiation in a medium of permittivity epsilon_(0) and permeability mu_(0) is given by:

The dimensions of e^(2)//4pi epsilon_(0)hc , where e, epsilon_(0),h and c are electronic charge, electric permittivity, Planck’s constant and velocity of light in vacuum respectively

The dimensions of e^(2)//4pi epsilon_(0)hc , where e, epsilon_(0),h and c are electronic charge, electric permittivity, Planck’s constant and velocity of light in vacuum respectively

The dimension of 1/(sqrt(mu_(0)epsilon_(0))) are same as

Which of the following does not have the dimensions of velocity ? ( Given epsilon_(0) is the permittivity of free space , mu_(0) is the permittivity of free space , v is frequency , lambda is wavelength , P is the pressure , and rho is density , k is wave number , omega is the the angular frequency)