A n-p-n transistor circuit has `alpha=0.985.` if `I_(C)=9mA` than the value of `I_(B)` is ………

Following current readings are obtained in a transistor circuit : I_(E) =2 mA and I_(B) =20 mu A. Compute the values of I_(C) and alpha .

For a transistor circuit, I_(B)=10mA and I_(C)=5.2mA ,

In common - emitter configuration of a transistor, the base current I_(E)=2muA, alpha=0.9 then the value of I_(C) is

In common - emitter configuration of a transistor, the base current I_(E)=2muA, alpha=0.9 then the value of I_(C) is

In a transistor, I_(c) = 20 mA, I_(b) =1 mA. What will be the value of alpha ?

In a transistor , I_c = 20 mA , I_b = 1 mA . What will be the value of alpha ?

In a common base configuration (transistor circuit) I_(E)=1mA, I_(C)=0.95mA . The value of base current is