In the previous question, the magnitude of velocity of particle at the mentioned instant is

In the previous question, the orbit velocity of the planet will be miniumu at

When a particle is projected at some angle with the horizontal, the path of the particle is parabolic. In the process the horizontal velocity remains constant but the magnitude of vertical velocity changes. At any instant during flight the acceleration of the particle remains g in vertically downward direction. During flight at any point the path of particle can be considered as a part of circle and radius of that circle is called the radius of curvature of the path Consider that a particle is projected with velocity u=10 m//s at an angle theta=60^(@) with the horizontal and take value of g=10m//s^(2) . Now answer the following questions. The magnitude of acceleration of particle at that instant is

In the previous question, the mean velocity of the rocket reaching the maximum height is :

In the previous question, the mean velocity of the rocket reaching the maximum height is :

In the previous question, the mean velocity of the rocket reaching the maximum height is :

For the previous question, the acceleration of the particle at any time t is :

For the previous question, the acceleration of the particle at any time t is :

For the previous question, the acceleration of the particle at any time t is :

At an instasnt t the coordinates of a particles are x=at^(2), y=bt^(2) and z=-0 . The magnitude of velocity of particle at an instant is