A particle moves from position `r_1=(3hati+2hatj-6hatk)` m to position `r_2=(14hati+13hatj+9hatk)` m under the action of a force `(4hati+hatj-3hatk)` N , then the work done is

A particle moved from position vec r_(1) = 3 hati + 2 hatj - 6 hatk to position vecr_(2) = 14 hati + 13 hatj +9 hatk undre the action of a force (4 hati + hatj +3 hatk) newtons . Find the work done .

a particle moves from position vector (3 hati + 2 hat j-6hatk) to the position vector (14hati+13hatj+9hatk) in metres under the action off a constant force of (4hati+hatj+3hatk) newton.Calculate the worrk done by the force.

A particle moves from position vecr_1=2hati+3hatj to position vecr_2=3hati+7hatj , under the action of a force (10 hati+13hatj) N Calculate the work done.

A body is displaced from position (hati+hatj+hatk) m to position (4hati+5hatj+6hatk) m under the action of force (5hati+4hatj-3hatk) N. The angle between the force and displcement vector is