A rectangular block of mass 5 kg is kept on a horizontal surface . The coefficient of friction between the block and the surface is `0.2` . If a force of 20 N is applied to the block at angle of `30^(@)` with the horizontal plane , what is the force of friction on the block ? (Take g = `10 m//s^(2)`)

A block of mass m is moving on a rough horizontal surface. mu is the coefficient of kinetic friction between the block and the surface. What is the net force exerted by the surface on the block?

A block of mass 5 kg is placed on a rough horizontal plane . The coefficients of stastic and kinetic friction between the block and surface are 0*5 and 0*3 respectively. A force of 100 N is applied at an angle 30^(@) with the horizontal as shown in the figure . The acceleration of the block will be [ g = 10 m//s^(2) ]

A block of mass 1kg lies on a horizontal surface in the truck, the coefficient of friction between the block and the surface is 0.6. If the acceleration of the truck is 5ms^(-2) the frictional force acting on the block is

A block of mass 4 kg is kept on a rough horizontal surface. The coefficient of static friction is 0.8. If a force of 19 N is applied on the block parallel to the floor, then the force of friction between the block and floor is

A block of mass 1 kg lies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is 5m//s^2 , the frictional force acting on the block is…………newtons.