`p(x) = x^(2)-x+k, p(1) = -1` then k = …………

A random variable x has its range {0,1,2} and the probabilities are given by P(x=0) =3k^(3), P(x=1) =4k-10k^(2) , P(x=2) =5k-1 where k is a constant then k=

When p(x) = x^(2) -8x +k leaves a remainder 6 when it is divided by (x-1) then k = ………….

If x - 1 is a factor of p(x) = kx^2 - 3x + k then value of k is :

A random variable x had its range {0, 1, 2} and the probabilities are given by P(x=0)=3k^(3), P(x=1)=4k-10k^(2), P(x=2)=5k-1 where k is constant then k =

If the sum of the zeroes of the polynomial p(x)=(k^(2)-14)x^(2)-2x-12 is 1 ,then value of k is

The p.m.f. of a.r.v. X is as follows: P( X=0) = 3k^ (3), P(X=1) = 4k-10k^ (2) , P(X=2)=5k-1, P(X=x)=0 for any other value of x, then value of k is

The p.m.f. of a.r.v. X is as follows: P( X=0) = 3k^ (3), P(X=1) = 4k-10k^ (2) , P(X=2)=5k-1, P(X=x)=0 for any other value of x, then value of k is

If (x + 1) be a factor of the polynomial p(x)=x^(3)+k , then k =