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Find the equation of the circle which ha...

Find the equation of the circle which has for its diameter the chord out off on the line` px+qy-1=0` by the circle `x^2+y^2 =a^2`

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Equation of any circle passing through the point(s) of intersection of circle S=0 and line L=0 is S + kL = 0 . Let P(x_1, y_1) be a point outside the circle x^2 + y^2 = a^2 and PA and PB be two tangents drawn to this circle from P touching the circle at A and B . On the basis of the above information : The circle which has for its diameter the chord cut off on the line px+qy - 1 = 0 by the circle x^2 + y^2 = a^2 has centre (A) (p/(p^2 + q^2), (-q)/(p^2 + q^2) (B) (p/(p^2 + q^2), (q)/(p^2 + q^2) (C) (p/(p^2 + q^2), (q)/(p^2 + q^2) (D) none of these

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