Home
Class 12
PHYSICS
A neutral water molecule (H(2)O) in its ...

A neutral water molecule `(H_(2)O)` in its vapour state has an electric dipole moment of magnitudes `6.4xx10^(-30)C-m`. How far apart are the molecules centres of positive and negative charge

Promotional Banner

Similar Questions

Explore conceptually related problems

A neutral water molecule (H_(2)O) in its vapor state has an electric dipole moment of magnitudes 6.4xx10^(-30)C-m . How far apart are the molecules centers of positive and negative charge

A neutral water molecule (H_(2)O) in its vapor state has an electric dipole moment of magnitude 6.2xx10^(-30)C*m . How far apart are the molecule's centers of positive and negative charge?

A neutral water molecule (H_2 O) in its vapour state has an electric dipole moment of magnitude 6.2 xx 10^-30 cm . a. How far apart are the molecules' centers of positive and negative charge ? b. If a molecule is placed in an electric field of 1.5 xx 10^4 NC^-1 , what maximum torque can the field exert on it ? (Such a field can easily be set up in the laboratory). c. How much work must an external agent do to turn this molecule end for end in this field, starting from its fully aligned position, for which theta = 0 ?

A neutral water molecule (H_2 O) in its vapour state has an electric dipole moment of magnitude 6.2 xx 10^-30 cm . a. How far apart are the molecules' centers of positive and negative charge ? b. If a molecule is placed in an electric field of 1.5 xx 10^4 NC^-1 , what maximum torque can the field exert on it ? (Such a field can easily be set up in the laboratory). c. How much work must an external agent do to turn this molecule end for end in this field, starting from its fully aligned position, for which theta = 0 ?

A neutral water molecule (H_(2)O) in its vapor state has an electric dipole moment of magnitude 6.2xx10^(-30)C*m . If the molecule is placed in a electric field of 1.5xx10^(4)N//C , what maximum torque can the field exert on it? (Such a field can easily be set up in the laboratory.)

A neutral water molecule (H_(2)O) in its vapor state has an electric dipole moment of magnitude 6.2xx10^(-30)C*m . How much work must an external agent do to rotate this molecule by 180^(@) in this field, starting from its fully aligned position , for which theta=0 ?

A water molecule has an electric dipole moment 6.4xx10^-30 Cm when it is in vapour state. The distance in metre between the centre of positive and negative charge of the molecule is