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A coil of natural length 40 cm and K = 1...

A coil of natural length 40 cm and K = `10^(3)` N m is used to suspend of a mass of 10 kg from its one end.
(i) calculate the stretched length of the coil.
(ii) If the mass is further pulled down by stretching the coil to a length of 46 cm and then released, then calculate the frequency of oscillation of the suspended mass ? (Consider spring to be massless)

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AI Generated Solution

To solve the problem step by step, we will break it down into two parts as per the question. ### Part (i): Calculate the Stretched Length of the Coil 1. **Identify the Given Data**: - Natural length of the coil, \( L_0 = 40 \, \text{cm} = 0.4 \, \text{m} \) - Spring constant, \( k = 10^3 \, \text{N/m} = 1000 \, \text{N/m} \) - Mass suspended, \( m = 10 \, \text{kg} \) ...
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