Home
Class 11
PHYSICS
A thin vertical tube of weight 12 g and ...

A thin vertical tube of weight 12 g and external diameter 1 cm is made to float vertically in water by placing 12 g of mercury at its bottom. If the tube is depressed slightly and then released, determine the time period of S.H.M.
Take `g = 10 m//s^(2)`

Text Solution

AI Generated Solution

To find the time period of the simple harmonic motion (SHM) of the floating tube, we can follow these steps: ### Step 1: Understand the System The system consists of a thin vertical tube with a weight of 12 g and an external diameter of 1 cm, which is floating in water. We have placed 12 g of mercury at the bottom of the tube. The total weight of the system is the weight of the tube plus the weight of the mercury. ### Step 2: Calculate the Total Weight The total weight (W) of the system is given by: \[ ...
Promotional Banner

Topper's Solved these Questions

  • OSCILLATIONS

    MODERN PUBLICATION|Exercise PRACTICE PROBLEMS|15 Videos
  • OSCILLATIONS

    MODERN PUBLICATION|Exercise PRACTICE PROBLEMS 2|20 Videos
  • MOTION IN A STRAIGHT LINE

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|16 Videos
  • PHYSICAL WORLD

    MODERN PUBLICATION|Exercise Revision exercises (Long answer questions)|6 Videos

Similar Questions

Explore conceptually related problems

A test tube of weight 5.6 g and external diameter 2.5 cm is allowed to float vertically in water by placing 10.4g of mercury at the bottom of the tube. The tube is depressed by a small amount and then released. Find the period of oscillation.

A test tube weighing 10g and external dismeter 2.5cm is floated vertically in water by placing 20g of mercury at its bottom. The tube is depressed in water a little and then released. Find the time of oscillation. Take g=10ms^(-2) .

A uniform solid bar of wood floats vertically in water with 10 cm of its height immersed in the water. When it is slightly depressed and released, it oscillates with a frequency of

A cubical body (side 0.1m and mass 0.002kg) floats in water. It is pressed and then released so that it executes SHM. Find the time period. (g=10m//s^(2))

A brass cube of side a and density sigma is floating in mercury of density rho . If the cube is displaced a bit vertically, it executes S.H.M. Its time period will be

A vertical U tube of uniform cross-section contains water up to a heigth of 0.5m . If water on one side is depressed a little and then released its motino up and down the two sides of the tube is SHM. Calculate (i) time period (ii) angular grequency of vibration. g=10ms^(2) .

A vertical U-tube of uniform cross-section contains water upto a height of 2.45 cm. show that if the water on one side is decpressed and then released, its up and down motion in the tube is SHM and calculate its time period. Given g=980cms^(-2) .

A ball is projected vertically up with speed 20 m/s. Take g=10m//s^(2)