A particle is executing simple harmonic motion having total energy of `2xx 10^(-3)` J and time period of `2pi` seconds. At `t = (pi)/(3)` second, the displacement of the particle is 0.11 m. Calculate the amplitude and mass of the particle.

Explanation

To solve the problem step by step, we will follow the outlined approach in the video transcript.

### Step 1: Find the Angular Frequency (ω)
The angular frequency (ω) can be calculated using the formula:
\[ \omega = \frac{2\pi}{T} \]
where \( T \) is the time period. Given that \( T = 2\pi \) seconds, we have:
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