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When a weight of 2kg is suspended from a...

When a weight of 2kg is suspended from a spring, its length increases by 3 cm. If the weight is further pulled down by 12 cm and then released, it executes S.H.M. What will be the period of oscillation of the arrangement ? Also calculate the potential energy of the spring .

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To solve the problem step by step, we will follow these steps: ### Step 1: Determine the Spring Constant (k) When a weight of 2 kg is suspended from the spring, it stretches the spring by 3 cm. We can use Hooke's Law, which states that the force exerted by a spring is proportional to its extension: \[ F_s = kx \] ...
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