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A particle executing S.H.M. has a maximu...

A particle executing S.H.M. has a maximum speed of 30`cm//s` and a maximum acceleration of `60cm//s^(2)`. The period of oscillation is

A

`pi` s

B

`(pi)/(2)s`

C

`2pi` s

D

`(pi)/(t)` s

Text Solution

Verified by Experts

The correct Answer is:
A
Given, `v_(max) = omegar = 30 cms^(-1)`
`alpha_(max) = omega^(2)r = 60 ms^(-1)`
`therefore (omega^(2)r)/(omegar) = (60)/(30) = 2`
or `omega = 2`
or `(2pi)/(T) =2`
or `T = pi` second `= pis`
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