The displacement time graph of a particle executing S.H.M. is shown in figure. Which of the following statement is `//` are true ?

Options

A. The force is zero at `t = (3T)/(4)`
B. The acceleration is maximum at `t = (4T)/(4)`
C. The velocity is maximum at `t = (T)/(4)`
D. The P.E. is equal to K.E. of oscillation at `t = (T)/(2)`.

Answer

A, B, C

Explanation

At `t = (3T)/(4)`, displacement, hence acceleration is zero, so force is zero.
At `t = (4T)/(4)`, displacement is maximum, hence acceleration is maximum.
At `t = (T)/(4)`, is the mean position, so velocity is maximum.
At `t = (T)/(2)`, is extreme position, so K.E. = 0 and P.E. = maximum.