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Show that the motion of a particle represented by `y=sinomegat-cosomegat` is simple harmonic with a period of `2pi//omega`.

Text Solution

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Given `y = sin omegat - cos omegat`
` = sqrt(2) [(1)/(sqrt(2)) sin omegat - (1)/(sqrt(2)) cos omegat]`
` = sqrt(2) [cos (pi)/(4)sin omegat - sin (pi)/(4)cos omegat]`
or `y = sqrt(2) sin (omegat - (pi)/(4))`
This represents S.H.M. having angular frequency of
`omega = (2pi)/(T)`
or `T = (2pi)/(omega)`
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