Consider a pair of identical pendulums, which oscillate with equal amplitude independently such that when one pendulum is at its extreme position making an angle of `2^(@)` to the right with the vertical , the other pendulum makes an angle of `1^(@)` to the left of the vertical. What is the phase difference between the pendulums?

Explanation

Angular displacement of the pendulum is given by
`theta_(1) = theta_(0) sin(omegat + delta_(1))`
`theta_(2) = theta_(0) sin (omegat + delta_(2))`
At extreme position `theta_(0) = 2` and this amplitude is same for each pendulum.
for the first pendulum `theta_(1) = 2^(@), therefore sin (omegat + delta_(1))=1`
`therefore sin (omegat + delta_(2)) = -1//2`
`therefore omegat + delta_(1) = 90^(@) , omegat + delta_(2) = 30`
`therefore delta_(1) - delta_(2) = 120^(@)`