A circular disc of mass 12 kg is suspended by a wire attached to its centre. The wire is twisted by rotating the disc and then released, so that the time period of torsional oscillation is 2 s. If the radius of the disc is 10 cm, then calculate the torsional spring constant of the wire.

Explanation

To solve the problem, we need to calculate the torsional spring constant \( C \) of the wire using the given information. The time period \( T \) of torsional oscillation is related to the moment of inertia \( I \) of the disc and the torsional spring constant \( C \) by the formula:

\[ T = 2\pi \sqrt{\frac{I}{C}} \]

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