For a simple pendulum, a graph is plotted its kinetic energy (KE) and potential energy (PE) against its displacement d. Which one of the following represents these correctly?

Options

A.
B.
C.
D.

Answer

A

Explanation

`v = omega sqrt(a^(2) - y^(2))`
K.E. ` = (1)/(2) momega^(2)(a^(2) - y^(2)),` P.E. ` = (1)/(2) momega^(2)y^(2)`
At mean position ` y = 0 , K.E._(max) = (1)/(2)momega^(2)a^(2)`
`P.E._(min) = 0`