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A sample of gas occupies 1.50 L at 25^(@...

A sample of gas occupies 1.50 L at `25^(@)C`. If the temperature is raised to `60^(@)C`, what is the new volume of the gas if pressure remains constant?

Text Solution

Verified by Experts

`V_(1)=1.50 L" "V_(2)=?`
`T_(1)=273+25=298K`
`T_(2)=60+273=333K`
Since pressure remains constant, therefore, by applying Charles. law
`(V_(1))/(T_(1))=(V_(2))/(T_(2))`
`"or "V_(2)=(V_(1)T_(2))/(T_(1))=((1.50L)xx(333K))/((298K))=1.68L`
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