At what temperature in centigrade will the volume of a gas at `0^(@)C` double itself, pressure remaining constant?

Explanation

Let the volume of the gas at `0^(@)C` be V.
`V_(1)=V`
`T_(1)=273+0=273K`
`T_(2)=2V`
`T_(2)=?`
Since pressure remains constant, therefore, by applying Charle.s law,
`(V_(1))/(T_(1))=(V_(2))/(T_(2))`
`(V)/(273)=(2V)/(T_(2))`
`T_(2)=(2Vxx273)/(V)=546K`
Changing the temperature to centigrade scale,
Temperature `=546-273=273^(@)C`.