A gas cylinder containing cooking gas can withsand a pressure of 14.9 atmosphere. The pressure gauge of the cylinder indicates 12 atmosphere at `27^(@)C`. Due to a sudden fire in the building the temperature starts rising. At what temperature will the cylinder explode ?

Explanation

Since gas is confined in a cylinder, its volume will remains constant
`{:("Initial conditions","Final conditions"),(p_(1)=12atm,p_(2)=14.9atm),(T_(1)=273+27=300K,T_(2)=?):}`
At constant volume
`(p_(1))/(T_(1))=(p_(2))/(T_(2))" or "T_(2)=(p_(2)T_(1))/(p_(1))`
`=(14.9xx300)/(12.0)=372.5K`
`"or Temperature at which cylinder explodes"`
`=372.5-273=99.5^(@)C`.