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Calculate the mass of 120 mL of N(2) at ...

Calculate the mass of 120 mL of `N_(2)` at `150^(@)C` and `1xx10^(5)Pa` pressure.

Text Solution

Verified by Experts

According to ideal gas equation,
`pV=nRT=(m)/(M)RT`
`["moles (n)"=("mass (m)")/("molecular mass (M)")]`
`m=(pVM)/(RT)`
`p=10^(5)Pa=10^(5)Nm^(-2),V=120xx10^(-6)m^(3)`
`M=28, T=273+150=423K,`
`R=8.314"N m K"^(-1)"mol"^(-1)`
`"Mass of gas, m"=(10^(5)Nm^(-2)xx120xx10^(-6)m^(3))/("8.314 N m mol"^(-1)K^(-1)xx423K)`
`=0.0955g`
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