Calculate the total pressure in a mixture og `8 g` of oxygen and `4 g` hydrogen confined in a vessel of `1 dm^(3)` at `27^(@)C`. `(R = 0.083 "bar" dm^(3) K^(-1) mol^(-1))`

Explanation

Partial pressure of oxygen gas,
`p=(nRT)/(V)`
`n=(8)/(32)" mol, "V="1 dm"^(3), T=300K`
`p_((O_(2)))=(8xx0.083xx300)/(32xx1)`
`="6.225 bar"`
Partial pressure of hydrogen gas
`p=(nRT)/(V)`
`n=(4)/(2)="2 mol"`
`p(H_(2))=(2xx0.083xx300)/(1)`
`="49.8 bar"`
`"Total pressure "=p_((O_(2)))+p_((H_(2)))`
`=6.225+49.8=56.025" bar"`.