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A neon-dioxygen mixture contains 70.6 g ...

A neon-dioxygen mixture contains 70.6 g dioxygen and 167.5 g neon. If pressure of the mixture of gases in the cylinder is 25 bar. What is the partial pressure of dioxygen and neon in the mixture ?

Text Solution

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`"No. of moles dioxigen"=(70.6)/(32)`
`="2.21 mol"`
`"No. of moles of neon"=(167.5)/(20)`
`="8.375 mol"`
`"Mole fraction of dioxygen, "x_(O_(2))=(2.21)/(2.21+8.375)`
`=0.21`
`"Mole fraction of neon, "x_(Ne)=(8.375)/(2.21+8.375)`
`=0.79`
`"Now partial pressure of a gas"="mole fraction"xx"total pressure"`
`therefore" Partial pressure of oxygen"=0.21xx("25 bar")`
`"Partial pressure of neon "=0.79xx("25 bar")`
`="19.75 bar."`
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