2.9 g of a gas at `95^(@)C` occupied the samme volume as 0.184 g of dhydrogen at `17^(@)C`, at the same pressure, what is the molar mass of the gas?

Answer

`"40 g mol"^(-1)`

Explanation

Volume occupied by 0.184 g of `H_(2)` gas at `17^(@)C` and pressure, p (say) may be calculated as :
`pV_(1)=nRT=(w)/(M)RT`
`"or "V_(1)=(w)/(M)RT=(0.814xx0.0821(273+17))/(2p)`
`=(2.1904)/(p)`
`"Volume occupied by 2.9 g of gas at "95^(@)C" at same pressure."`
`V_(2)=(w)/(Mp)RT=(2.9xx0.0821xx368)/(Mp)`
`(2.1904)/(p)=(2.9xx0.0821xx368)/(Mp)`
`M=(2.9xx0.0821xx368)/(2.1904)="40 g mol"^(-1)`