`20%N_(2)O_(4)` molecules are dissociated in a sample of gas at `27^(@)C` and 760 torr. Calculate the density of the equilibrium mixture.

Answer

`"3.11 gL"^(-1)`

Explanation

At equilibrium,. `20%` i.e., 0.2 moles is dissociated
`{:(,N_(2)O_(4),hArr,2NO_(2)),("initial conc.",1,,0),("At equ.",(1-0.2),,2xx0.2):}`
`"Molar mass of mixture"=(0.8xx92+0.4xx46)/(0.8+0.4)=76.66`
`pV=(w)/(M)=RT`
`"or "d=(w)/(V)=(pxxM)/(RT)=(1xx76.66)/(0.082xx300)="3.11 g L"^(-1)`.