A `2.5 L` flask contains `0.25 mol` each of sulphur dioxide and nitrogen gas at `27^(@)C`. Calculate the partial pressure exerted by each gas and also the total pressure.

Answer

`4.98xx10^(5)Pa`

Explanation

Partial pressure of gases,
`p(SO_(2))=(nRT)/(V)=(0.25xx8.314xx300)/(2.5xx10^(-3))=2.49xx10^(5)Pa`
`p(N_(2))=(nRT)/(V)=(0.25xx8.314xx300)/(2.5xx10^(-3))=2.49xx10^(5)Pa`
`P_("total")=2.49xx10^(5)+2.49xx10^(5)=4.98xx10^(5)Pa.`